r^2-17r-1734=0

Solution for r^2-17r-1734=0 equation:

r^2-17r-1734=0

a = 1; b = -17; c = -1734;
Δ = b2-4ac
Δ = -172-4·1·(-1734)
Δ = 7225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7225}=85$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-85}{2*1}=\frac{-68}{2}
=-34
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+85}{2*1}=\frac{102}{2}
=51
$